C Program to Display All Characters Present in the Prime Position of a String

This is a C Program to display the characters in prime position of a given string.

Problem Description

This program prints the characters in prime position of a given string.

Problem Solution

1. Take a string as input.
2. Find the number which gets divided only once and consecutively print the character of the obtained position.

Program/Source Code

Here is source code of the C Program to display the characters in prime position a given string. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

```
/*
```

 * C Program to Display the Characters in Prime Position a given String

```
 */
```
```
#include <stdio.h>
```
```
#include <string.h>
```
```
 
```
```
void main()
```
```
{
```
```
    int i, j, k, count = 0;
```
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    char str[50];
```
```
 
```
```
    printf("enter string\n");
```
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    scanf("%[^\n]s", str);
```
```
    k = strlen(str);
```

    printf("prime characters in a string are\n");

```
    for (i = 2;i <= k;i++)
```
```
    {    
```
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        count = 0;
```
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        for (j = 2;j <= k;j++)
```
```
        {
```
```
            if (i % j == 0)
```
```
            {
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                count++;
```
```
            }
```
```
        }
```
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        if (count == 1)
```
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        {
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            printf("%c\n", str[i - 1]);
```
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        }
```
```
    }
```
```
}
```

Program Explanation

1. Take a string as input and store it in the array str[].
2. Store the length of the input string in the variable k.
3. Use two loops to divide the numbers upto the value of k.
4. Increment the variable count when the remainder is zero.
5. If the variable count is equal to 1, then print the corresponding character.

Runtime Test Cases

enter string
welcome to sanfoundry c-programming class!
prime characters in a string are
e
l
o
e
 
a
u
d
c
r
m
c
s

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