C Program to Count the Occurrences of Elements in a Linked List without Recursion

This C Program, using iteration, finds the occurrence for an element in an unsorted list. The user enters the element need to be counted.

Here is the source code of the C program to find the number of occurrences of a given number in a list. The C Program is successfully compiled and run on a Linux system. The program output is also shown below.

```
/*
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 * C Program Count the Number of Occurrences of an Element in the Linked List

```
 * without using Recursion
```
```
 */
```
```
#include <stdio.h>
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```
 
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int occur(int [], int, int);
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```
 
```
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int main()
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{
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    int size, key, count;
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    int list[20];
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    int i;
```
```
 
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    printf("Enter the size of the list: ");

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    scanf("%d", &size);
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    printf("Printing the list:\n");
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    for (i = 0; i < size; i++)
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```
    {
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        list[i] = rand() % size;
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        printf("%d    ", list[i]);
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    }
```

    printf("\nEnter the key to find it's occurence: ");

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    scanf("%d", &key);
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    count = occur(list, size, key);
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    printf("%d occurs for %d times.\n", key, count);

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    return 0;
```
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}
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```
 
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int occur(int list[], int size, int key)

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{
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    int i, count = 0;
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```
 
```
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    for (i = 0; i < size; i++)
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    {
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        if (list[i] == key)
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        {
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            count += 1;
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        }
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    }
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    return count;
```
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}
```

$ gcc occurnumber.c -o occurnumber
$ a.out
Enter the size of the list: 10
Printing the list:
3    6    7    5    3    5    6    2    9    1   
Enter the key to find it's occurence: 3
3 occurs for 2 times.

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If you wish to look at other example programs on Linked List, go to Linked List. If you wish to look at programming examples on all topics, go to C Programming Examples.

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