Hexadecimal to Binary in C

This is a C program to Convert Hexadecimal to Binary.

Problem Description

This program takes a hexadecimal number and converts to binary number.

Problem Solution

1. Take a hexadecimal number as input.
2. For each bit of a hexadecimal number print its equivalent binary number in a four bit fashion. Example: For 22 print it as 0010 0010.
3. Use switch statement to access each bit of a hexadecimal number.

Program/Source Code

Here is source code of the C program to Convert Hexadecimal to Binary. The C program is successfully compiled and run on a Linux system. The program output is also shown
below.

```
/*
```

 * C Program to Convert Hexadecimal to Binary

```
 */
```
```
#include <stdio.h>
```
```
#define MAX 1000
```
```
 
```
```
int main()
```
```
{
```
```
    char binarynum[MAX], hexa[MAX];
```
```
    long int i = 0;
```
```
 
```

    printf("Enter the value for hexadecimal ");

```
    scanf("%s", hexa);
```

    printf("\n Equivalent binary value: ");

```
    while (hexa[i])
```
```
    {
```
```
        switch (hexa[i])
```
```
        {
```
```
        case '0':
```
```
            printf("0000"); break;
```
```
        case '1':
```
```
            printf("0001"); break;
```
```
        case '2':
```
```
            printf("0010"); break;
```
```
        case '3':
```
```
            printf("0011"); break;
```
```
        case '4':
```
```
            printf("0100"); break;
```
```
        case '5':
```
```
            printf("0101"); break;
```
```
        case '6':
```
```
            printf("0110"); break;
```
```
        case '7':
```
```
            printf("0111"); break;
```
```
        case '8':
```
```
            printf("1000"); break;
```
```
        case '9':
```
```
            printf("1001"); break;
```
```
        case 'A':
```
```
            printf("1010"); break;
```
```
        case 'B':
```
```
            printf("1011"); break;
```
```
        case 'C':
```
```
            printf("1100"); break;
```
```
        case 'D':
```
```
            printf("1101"); break;
```
```
        case 'E':
```
```
            printf("1110"); break;
```
```
        case 'F':
```
```
            printf("1111"); break;
```
```
        case 'a':
```
```
            printf("1010"); break;
```
```
        case 'b':
```
```
            printf("1011"); break;
```
```
        case 'c':
```
```
            printf("1100"); break;
```
```
        case 'd':
```
```
            printf("1101"); break;
```
```
        case 'e':
```
```
            printf("1110"); break;
```
```
        case 'f':
```
```
            printf("1111"); break;
```
```
        default:
```

            printf("\n Invalid hexa digit %c ", hexa[i]);

```
            return 0;
```
```
        }
```
```
        i++;
```
```
    }
```
```
    return 0;
```
```
}
```

Program Explanation

1. Take a hexadecimal number as input and store it in the array hexa.
2. Using switch statement access each bit of the hexadecimal number and print its equivalent binary number in a four bit fashion as shown in the program.
3. Do step 2 for every bit of a input number. Use while loop to do this.

Runtime Test Cases

Output:
 
Enter the value for hexadecimal ab
Equivalent binary value: 10101011

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