This is a C program to find whether a given year is leap year or not.
This program takes a year as input and finds whether a year is leap year or not.
1. Take a year as input.
2. Check whether a given year is divisible by 400.
3. Check whether a given year is divisible by 100.
4. Check whether a given year is divisible by 4.
5. If the condition at step 2 and 4 becomes true, then the year is a leap year.
6. If the condition at step 3 becomes true, then the year is not a leap year.
Here is source code of the C program to check a given year is leap year. The C program is successfully compiled and run on a Linux system. The program output is also shown below.
/** C program to find whether a given year is leap year or not*/void main()
{int year;
printf("Enter a year \n");
scanf("%d", &year);
if ((year % 400) == 0)
printf("%d is a leap year \n", year);
else if ((year % 100) == 0)
printf("%d is a not leap year \n", year);
else if ((year % 4) == 0)
printf("%d is a leap year \n", year);
elseprintf("%d is not a leap year \n", year);
}
1. Take a year as input and store it in the variable year.
2. Using if,else statements to,
a) Check whether a given year is divisible by 400.
b) Check whether a given year is divisible by 100.
c) Check whether a given year is divisible by 4.
3. If the condition at step 2.a becomes true, then print the ouput as “It is a leap year”.
4. If the condition at step 2.b becomes true, then print the ouput as “It is not a leap year”.
5. If the condition at step 2.c becomes true, then print the ouput as “It is a leap year”.
6. If neither of the condition becomes true, then the year is not a leap year and print the same.
Enter a year 2012 2012 is a leap year Enter a year 2009 2009 is not a leap year
Sanfoundry Global Education & Learning Series – 1000 C Programs.
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