This C program, using iteration, displays the alternate nodes in a linked list.A linked list is an ordered set of data elements, each containing a link to its successor.
Here is the source code of the C program to display a linked list in reverse. The C program is successfully compiled and run on a Linux system. The program output is also shown below.
/*
* C Program to Print the Alternate Nodes in a Linked List without
* using Recursion
*/
#include <stdio.h>
#include <stdlib.h>
struct node
{
int a;
struct node *next;
};
void generate(struct node **);
void display(struct node *);
void delete(struct node **);
int main()
{
struct node *head = NULL;
generate(&head);
printf("\nDisplaying the alternate nodes\n");
display(head);
delete(&head);
return 0;
}
void display(struct node *head)
{
int flag = 0;
while(head != NULL)
{
if (!(flag % 2))
{
printf("%d ", head->a);
}
flag++;
head = head->next;
}
}
void generate(struct node **head)
{
int num, i;
struct node *temp;
printf("Enter length of list: ");
scanf("%d", &num);
for (i = num; i > 0; i--)
{
temp = (struct node *)malloc(sizeof(struct node));
temp->a = i;
if (*head == NULL)
{
*head = temp;
(*head)->next = NULL;
}
else
{
temp->next = *head;
*head = temp;
}
}
}
void delete(struct node **head)
{
struct node *temp;
while (*head != NULL)
{
temp = *head;
*head = (*head)->next;
free(temp);
}
}}
$ gcc alter_iter.c -o alter_iter $ a.out Enter length of list: 20 Displaying the alternate nodes 1 3 5 7 9 11 13 15 17 19
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