Bioprocess Engineering Questions and Answers – Errors in Data and Calculations

This set of Bioprocess Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Errors in Data and Calculations”.

1. What is the rounding off of a number?
a) To change a number to its nearest prime number
b) To change a number to its nearest odd number
c) To change a number to its nearest whole number
d) To change a number to its nearest even number
View Answer

Answer: c
Explanation: To reduce successively the number of digits to the right of the decimal point of a mixed number by dropping the final digit and adding 1 to the next preceding digit if the dropped digit was 5 or greater, or leaving the preceding digit unchanged if the dropped digit was 4 or less.

2. Round off the number 425.68 to Tenths (1 decimal place), Hundredths (2 decimal place) and to Tens place?
a) 425.6, 425.68, 426
b) 425.7, 425.68, 430
c) 425.5, 426.78, 425
d) 425.7, 4257, 430
View Answer

Answer: b
Explanation: In the Tenths (1 decimal place), we will take 68 as a digit after the decimal and round off it to the multiple of ten as 70, In the hundredths (2 decimal place), we will take both 68 as a number after the decimal because we have to take 2 decimal places and 6,8 both numbers are greater than 5, In the Tens place, we will round the number before the decimal place to the closest multiple of ten, i.e. 430.

3. A piece of iron rod was measured and found to be 120cms. But the actual value of the wood is 123cms. Find the relative error?
a) 3%
b) 2.5%
c) 2.43%
d) 3.43%
View Answer

Answer: c
Explanation: Given:
True value = 123cms
Measured value = 120cms
Firstly, let us find out the absolute error.
We know by subtracting true value with measured value we get absolute error = 123 – 120 = 3cms
Therefore, absolute error = 3cms
Now, let us find out the relative error = absolute error/True value x 100
= 3/123 x 100 = 2.43%
Therefore, the relative error for the given values = 2.43%.

4. Which of the following is correct according to calculating relative error as a measure of Precision?
a) (Absolute error/ True value)*100
b) (Absolute error/True value)
c) (measurement being taken/Absolute error)*100
d) (Absolute error/measurement being taken)
View Answer

Answer: d
Explanation: Relative error (RE) — when used as a measure of precision — is the ratio of the absolute error of a measurement to the measurement being taken. In other words, this type of error is relative to the size of the item being measured. RE is expressed as a percentage and has no units.

5. From the below data which one is precise?

Sample A: 15.38, 15.37, 15.36, 15.33, and 15.32.
Sample B: 32.56, 32.55, 32.48, 32.49 and 32.48.
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a) Sample A
b) Sample B
c) Sample A & B
d) None of the mentioned
View Answer

Answer: a
Explanation: Subtract the lowest data point from the highest:
Sample A: 15.38 – 15.32 = 0.06
Sample B: 32.56 – 32.48 = 0.08
Sample A has the lowest range (.06) and so is the more precise.

6. If a student measured the mass of an object on a balance three times and obtained the values 14.568 g, 14.566 g, and 14.565 g, the range and percent of the average value between the measurements would be ____________
a) 0.005gm, 0.01%
b) 0.004gm,0.02%
c) 0.003gm,0.02%
d) 0.001gm,0.01%
View Answer

Answer: c
Explanation: Range = (14.568 – 14.565) g = 0.003 g,
This is a reasonable range; the uncertainty appears in the last significant figure of the measured value, as it should.
The average value for the mass of the object is 14.566 g. Therefore:
% of average = (0.003 g/14.566 g) x 100% = 0.02%
the range as a percent of average (RPA) has only one significant figure in this case because the numerator of the fraction has only one.

7. The accepted value for the density of gold metal is 19.31 g/cm3. If a student measured the mass and volume of a sample of gold, and obtained a value of 19.03 g/cm3, the percent difference would be ______
a) -1.5%
b) 1.5%
c) -0.5%
d) 0.5%
View Answer

Answer: a
Explanation: % difference = [(19.03 – 19.31) g/19.31 g] x 100% = – 1.5%
A percent difference can be positive or negative; the sign shows whether the experimental value is higher or lower than the actual or theoretical value. This distinction is not used in precision since all values are experimental.

8. A group of students worked in separate teams to measure the length of an object. Here are their data: Find out:-
i) The average length
ii) The range or spread
iii) The precision of the measurement
a) 2.7, 0.2, 2.7±0.2
b) 2.8, 0.1, 2.8±0.1
c) 2.0, 0.1, 2.0±0.1
d) 2.0, 0.2, 2.0±0.2
View Answer

Answer: a
Explanation: The average length is the mean or average, in which the summation of the total number is divided from the total number, i.e.
(2.65+2.60+2.77+2.80+2.75)cm/5 = 13.57cm/5 = 2.714cm or 2.7cm
The range or spread is the subtraction from the highest value from the lowest value, i.e.,
Highest value = 2.80cm
Lowest value = 2.60cm
Therefore, Range = 2.80cm-2.60cm = 0.2cm
The precision of the measurement can be shown as average± range cm, i.e.,
Average = 2.7cm
Range = 0.2cm
Therefore, Precision = 2.7±0.2cm.

9. You are given a cube of pure copper. You measure the sides of the cube to find the volume and weigh it to find its mass. When you calculate the density using your measurements, you get 8.78 grams/cm3. Coppers accepted density is 8.96 g/cm3. What is your percent error?
a) 1%
b) 0.02%
c) 0.01%
d) 2%
View Answer

Answer: d
Explanation: Experimental value = 8.78 g/cm3
Accepted value = 8.96 g/cm3
Step 1: Subtract the accepted value from the experimental value.
8.78 g/cm3 – 8.96 g/cm3 = -0.18 g/cm3
Step 2: Take the absolute value of step 1
|-0.18 g/cm3| = 0.18 g/cm3
Step 3: Divide that answer by the accepted value, 0.18g/cm3 ÷ 8.96g/cm3 = 0.02
Step 4: Multiply that answer by 100 and add the % symbol to express the answer as a percentage.
0.02 x 100 = 2
The percent error of your density calculation was 2%.

10. What type of surface you would observe in the case of mercury with glass?
a) Concave meniscus
b) Convex meniscus
c) Contact angle = 180°
d) Contact angle = 0°
View Answer

Answer: b
Explanation: A convex meniscus occurs when the molecules have a stronger attraction to each other than to the container and Mercury does not wet glass – the cohesive forces within the drops i.e., bond between the molecules of mercury are stronger than the adhesive forces between the drops and glass.

11. You will read the meniscus reading as you measure the level at the horizontal center or inside part of the meniscus.
a) True
b) False
View Answer

Answer: a
Explanation: Place the graduated cylinder on a flat surface and view the height of the liquid in the cylinder with your eyes directly level with the liquid. The liquid will tend to curve downward. This curve is called the meniscus. Always read the measurement at the bottom of the meniscus.

Sanfoundry Global Education & Learning Series – Bioprocess Engineering.

To practice all areas of Bioprocess Engineering, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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