This set of Advanced Fluid Mechanics Questions and Answers focuses on “Geometrical Properties of Triangular Section – 2”.

1. Determine the Hydraulic depth for a triangular channel having side slope of 1H:3V and depth 15m.

a) 30m

b) 15m

c) 7.5m

d) 3.75m

View Answer

Explanation: Hydraulic Depth = y/2

= 15/2

= 7.5m.

2. Calculate the Hydraulic Radius for a triangular channel having side slope 2H:4V and a depth of 3m.

a) 0.68m

b) 0.67m

c) 0.66m

d) 0.65m

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3. The Hydraulic Depth of a triangular channel is 5m, calculate the normal depth of the channel.

a) 8m

b) 10m

c) 12m

d) 14m

View Answer

Explanation: D = y/2

y = 2D = 10m.

4. The hydraulic radius of a triangular section is 0.45m and the normal depth of the channel is 2m, calculate the side slope of the channel.

a) 1/4

b) 1/3

c) 1/2

d) 1

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5. The ratio between hydraulic radius and hydraulic depth of a triangular channel is 31/100, calculate the side slope of the channel.

a) 1⁄2

b) 1⁄3

c) 1⁄4

d) 2⁄3

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6. Calculate the wetted perimeter of a triangular channel section having a depth of 5m and the side slope is equal to tan 30°.

a) 9.54m

b) 10.54m

c) 11.54m

d) 12.54m

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7. The discharge of water through a triangular section is 90m^{3}⁄s and velocity of flow is 5 m⁄s. Calculate the hydraulic depth of the channel having a side slope 1⁄2.

a) 2m

b) 3m

c) 4m

d) 5m

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8. The top width of a triangular channel section is 4m and the depth of the section is 8m, calculate the wetted perimeter of the channel.

a) 16.5m

b) 17.5m

c) 18.5m

d) 19.5m

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9. In the given figure the vertical angle is 60°, calculate the wetted area of the channel.

a) 23.3m^{2}

b) 33.3m^{2}

c) 43.3m^{2}

d) 53.3m^{2}

View Answer

Explanation: Area = (5 tan60°)(5)

Area = 43.3m

^{2}.

**Sanfoundry Global Education & Learning Series – Fluid Mechanics.**

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