# Fluid Mechanics Questions and Answers – Geometrical Properties of Triangular Section – 2

This set of Advanced Fluid Mechanics Questions and Answers focuses on “Geometrical Properties of Triangular Section – 2”.

1. Determine the Hydraulic depth for a triangular channel having side slope of 1H:3V and depth 15m.
a) 30m
b) 15m
c) 7.5m
d) 3.75m

Explanation: Hydraulic Depth = y/2
= 15/2
= 7.5m.

2. Calculate the Hydraulic Radius for a triangular channel having side slope 2H:4V and a depth of 3m.
a) 0.68m
b) 0.67m
c) 0.66m
d) 0.65m

Explanation:

3. The Hydraulic Depth of a triangular channel is 5m, calculate the normal depth of the channel.
a) 8m
b) 10m
c) 12m
d) 14m

Explanation: D = y/2
y = 2D = 10m.

4. The hydraulic radius of a triangular section is 0.45m and the normal depth of the channel is 2m, calculate the side slope of the channel.
a) 1/4
b) 1/3
c) 1/2
d) 1

Explanation:

5. The ratio between hydraulic radius and hydraulic depth of a triangular channel is 31/100, calculate the side slope of the channel.
a) 1⁄2
b) 1⁄3
c) 1⁄4
d) 2⁄3

Explanation:
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6. Calculate the wetted perimeter of a triangular channel section having a depth of 5m and the side slope is equal to tan⁡ 30°.
a) 9.54m
b) 10.54m
c) 11.54m
d) 12.54m

Explanation:

7. The discharge of water through a triangular section is 90m3⁄s and velocity of flow is 5 m⁄s. Calculate the hydraulic depth of the channel having a side slope 1⁄2.
a) 2m
b) 3m
c) 4m
d) 5m

Explanation:

8. The top width of a triangular channel section is 4m and the depth of the section is 8m, calculate the wetted perimeter of the channel.
a) 16.5m
b) 17.5m
c) 18.5m
d) 19.5m

Explanation:

9. In the given figure the vertical angle is 60°, calculate the wetted area of the channel.

a) 23.3m2
b) 33.3m2
c) 43.3m2
d) 53.3m2

Explanation: Area = (5 tan⁡60°)(5)
Area = 43.3m2.

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