Fluid Mechanics Questions and Answers – Geometrical Properties of Triangular Section – 2

This set of Advanced Fluid Mechanics Questions and Answers focuses on “Geometrical Properties of Triangular Section – 2”.

1. Determine the Hydraulic depth for a triangular channel having side slope of 1H:3V and depth 15m.
a) 30m
b) 15m
c) 7.5m
d) 3.75m
View Answer

Answer: c
Explanation: Hydraulic Depth = y/2
= 15/2
= 7.5m.

2. Calculate the Hydraulic Radius for a triangular channel having side slope 2H:4V and a depth of 3m.
a) 0.68m
b) 0.67m
c) 0.66m
d) 0.65m
View Answer

Answer: b
Explanation:
Hydraulic Radius for triangular channel having side slope 2H:4V & depth of 3m is 0.67m

3. The Hydraulic Depth of a triangular channel is 5m, calculate the normal depth of the channel.
a) 8m
b) 10m
c) 12m
d) 14m
View Answer

Answer: b
Explanation: D = y/2
y = 2D = 10m.
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4. The hydraulic radius of a triangular section is 0.45m and the normal depth of the channel is 2m, calculate the side slope of the channel.
a) 1/4
b) 1/3
c) 1/2
d) 1
View Answer

Answer: c
Explanation:
Side slope of the channel is 1/2 if hydraulic radius of a triangular section is 0.45m

5. The ratio between hydraulic radius and hydraulic depth of a triangular channel is 31/100, calculate the side slope of the channel.
a) 1⁄2
b) 1⁄3
c) 1⁄4
d) 2⁄3
View Answer

Answer: b
Explanation:
Side slope is 1/3 if ratio between radius & hydraulic depth of triangular is 31/10
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6. Calculate the wetted perimeter of a triangular channel section having a depth of 5m and the side slope is equal to tan⁡ 30°.
a) 9.54m
b) 10.54m
c) 11.54m
d) 12.54m
View Answer

Answer: c
Explanation:
Perimeter of triangular having depth of 5m & side slope is equal to tan⁡ 30° is 11.54m

7. The discharge of water through a triangular section is 90m3⁄s and velocity of flow is 5 m⁄s. Calculate the hydraulic depth of the channel having a side slope 1⁄2.
a) 2m
b) 3m
c) 4m
d) 5m
View Answer

Answer: b
Explanation:
The hydraulic depth of the channel having a side slope 1/2 is 3m
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8. The top width of a triangular channel section is 4m and the depth of the section is 8m, calculate the wetted perimeter of the channel.
a) 16.5m
b) 17.5m
c) 18.5m
d) 19.5m
View Answer

Answer: a
Explanation:
The wetted perimeter of channel is 16.5m if top width of triangular channel section is 4m

9. In the given figure the vertical angle is 60°, calculate the wetted area of the channel.
Find the wetted area of the channel in the given figure the vertical angle is 60°
a) 23.3m2
b) 33.3m2
c) 43.3m2
d) 53.3m2
View Answer

Answer: c
Explanation: Area = (5 tan⁡60°)(5)
Area = 43.3m2.
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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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