# Fluid Mechanics Questions and Answers – Geometrical Properties of Triangular Section – 2

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This set of Advanced Fluid Mechanics Questions and Answers focuses on “Geometrical Properties of Triangular Section – 2”.

1. Determine the Hydraulic depth for a triangular channel having side slope of 1H:3V and depth 15m.
a) 30m
b) 15m
c) 7.5m
d) 3.75m

Explanation: Hydraulic Depth = y/2
= 15/2
= 7.5m.

2. Calculate the Hydraulic Radius for a triangular channel having side slope 2H:4V and a depth of 3m.
a) 0.68m
b) 0.67m
c) 0.66m
d) 0.65m

3. The Hydraulic Depth of a triangular channel is 5m, calculate the normal depth of the channel.
a) 8m
b) 10m
c) 12m
d) 14m

Explanation: D = y/2
y = 2D = 10m.

4. The hydraulic radius of a triangular section is 0.45m and the normal depth of the channel is 2m, calculate the side slope of the channel.
a) 1/4
b) 1/3
c) 1/2
d) 1

5. The ratio between hydraulic radius and hydraulic depth of a triangular channel is 31/100, calculate the side slope of the channel.
a) 1⁄2
b) 1⁄3
c) 1⁄4
d) 2⁄3

6. Calculate the wetted perimeter of a triangular channel section having a depth of 5m and the side slope is equal to tan⁡ 30°.
a) 9.54m
b) 10.54m
c) 11.54m
d) 12.54m

7. The discharge of water through a triangular section is 90m3⁄s and velocity of flow is 5 m⁄s. Calculate the hydraulic depth of the channel having a side slope 1⁄2.
a) 2m
b) 3m
c) 4m
d) 5m

8. The top width of a triangular channel section is 4m and the depth of the section is 8m, calculate the wetted perimeter of the channel.
a) 16.5m
b) 17.5m
c) 18.5m
d) 19.5m

9. In the given figure the vertical angle is 60°, calculate the wetted area of the channel. a) 23.3m2
b) 33.3m2
c) 43.3m2
d) 53.3m2

Explanation: Area = (5 tan⁡60°)(5)
Area = 43.3m2.

Sanfoundry Global Education & Learning Series – Fluid Mechanics. 