1. Is the function y[n] = cos(x[n]) periodic or not?

a) Aperiodic

b) periodic

View Answer

Explanation: ‘y’ will be periodic only if x attains the same value after some time, T. However, if x is a one-one discrete function, it may not be possible for some x[n].

2. If n tends to infinity, is the accumulator function an unstable one?

a) The function is marginally stable

b) The function is unstable

c) The function is stable

View Answer

Explanation: The system would be unstable, as the output will grow out of bound at the maximally worst possible case.

3. Comment on the causality of the following discrete time system: y[n] = x[-n]
a) Causal

b) Non causal

View Answer

Explanation: For positive time, the output depends on the input at an earlier time, giving causality for this portion. However, at a negative time, the output depends on the input at a positive time, i.e. at a time in the future, rendering it non causal.

4. Comment on the causality of the discrete time system: y[n] = x[n+3]
a) Causal

b) Non Causal

c) Anti Causal

View Answer

Explanation: The output always depends on the input at a time in the future, rendering it anti-causal.

a) Yes

b) No

View Answer

Explanation: As we give two inputs, x1 and x2, and give an added input x1 and x2, we do not get the corresponding y1 and y2. Thus, additive rule is disturbed and hence the system is not linear.

6.Comment on the time invariance of the following discrete system: y[n] = x[2n+4].

a) Time invariant

b) Time variant

View Answer

Explanation: A time shift in the input scale gives double the time shift in the output scale, and hence is time variant.

7. Is the function y[2n] = x[2n] linear in nature?

a) Yes

b) No

View Answer

Explanation: The function obeys both additivity and homogeneity properties. Hence, the function is linear.

8. How is a linear function described as?

a) Zero in Finite out

b) Zero in infinite out

c) Zero in zero out

d) Zero in Negative out

View Answer

Explanation: The system needs to give a zero output for a zero input so as to conserve the law of additivity, to ensure linearity.

a) Yes

b) No

View Answer

Explanation: The system is not linear, as x1^2 + x2^2 is not equal to (x1+x2)^2.

10. Is the above system, i.e y[n] = x^2[n-2] time invariant?

a) Yes

b) No

View Answer

Explanation: A time shift of t0 will still result in an equivalent time shift of t0 in the output, and hence will be time invariant.

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