This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Transmission(ABCD) Parameters”.
1.In the circuit shown below, find the transmission parameter A.
a) 6/5
b) 5/6
c) 3/4
d) 4/3
View Answer
Explanation: Open circuiting b-b‘, V1 = 6 I1, V2 = 5I1. On solving V1/V2 = 6/5. On substituting we get A = V1/V2=6/5.
2. In the circuit shown below, find the transmission parameter C.
a) 4/5
b) 3/5
c) 2/5
d) 1/5
View Answer
Explanation: C = I1/V2|I2=0. By open circuiting b-b‘ we get V2 = 5 I1 => I1/V2 = 1/5. On substituting we get C = I1/V2=1/5 Ω.
3. In the circuit shown below, find the transmission parameter B.
a) 15/5
b) 17/5
c) 19/5
d) 21/5
View Answer
Explanation: The transmission parameter B is given by B = -V1/I2|V2=0. Short circuiting b-b‘, -I2 = 5/17 V1 => -V1/I2 = 17/5. On substituting we get B=17/5 Ω.
4. In the circuit shown below, find the transmission parameter D.
a) 1/5
b) 3/5
c) 7/5
d) 9/5
View Answer
Explanation: D is a transmission parameter and is given by D = -I1/I2 |V2=0. Short circuiting b-b‘, I1 = 7/17 V1 and-I2 = 5/17 V1. So we get I1/I2 = 7/5. So D=7/5.
5. The hybrid parameter h11 is called?
a) short circuit input impedance
b) short circuit forward current gain
c) open circuit reverse voltage gain
d) open circuit output admittance
View Answer
Explanation: h11=V1/I1 |V2=0. So the hybrid parameter h11 is called short circuit input impedance.
6. The hybrid parameter h21 is called?
a) open circuit output admittance
b) open circuit reverse voltage gain
c) short circuit forward current gain
d) short circuit input impedance
View Answer
Explanation: h21=I2/I1 |V2=0. So the hybrid parameter h21 is called short circuit forward current gain.
7. In the circuit shown below, find the h-parameter h11.
a) 1
b) 2
c) 3
d) 4
View Answer
Explanation: h11=V1/I1 |V2=0. So short circuiting b-b‘, V1 = I1((2||2)+1) = 2I1 => V1/I1 = 2. On substituting we get h11 = V1/I1 = 2Ω.
8. In the circuit shown below, find the h-parameter h21.
a) 1
b) -1
c) 1/2
d) -1/2
View Answer
Explanation: Short circuiting b-b‘, h21 = I2/I1 when V2=0 and -I2 = I1/2 => I2/I1 = -1/2. So h21 = -1/2.
9. In the circuit shown below, find the h-parameter h12.
a) 1/2
b) -1/2
c) 1
d) -1
View Answer
Explanation: Open circuiting a-a‘ we get V1=Iy×2 and
Iy=I2/2 and V2=Ix×4 and Ix=I2/2. On solving and substituting, we get h12 = V1/V2=1/2.
10. In the circuit shown below, find the h-parameter h22.
a) 1
b) 2
c) 1/2
d) 3/2
View Answer
Explanation: Open circuiting a-a‘ we get V1=Iy×2 and Iy=I2/2 and V2=Ix×4 and Ix=I2/2. On solving and substituting, we get h22 =I2/V2=1/2 Ω.
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