Network Theory Questions and Answers – Voltage and Current Values of a Sine Wave

This set of Network Theory Questions and Answers for Experienced people focuses on “Voltage and Current Values of a Sine Wave”.

1. Find the instantaneous value of the sine value at 90⁰ point having an amplitude 10V and time period 360⁰.
a) 5
b) 10
c) 15
d) 20
View Answer

Answer: b
Explanation: The equation for sine wave A is v(t) = 10sinωt. The value at 90⁰ in this wave is v (t) = 10sin90⁰ = 10V.

2. Find the instantaneous value at 90⁰ point of the sine wave if the wave is shifted by 45⁰.
a) 5.66
b) 6.66
c) 7.66
d) 8.66
View Answer

Answer: a
Explanation: The equation for sine wave A is v(t) = 10sinωt. The equation for sine wave A is v(t) = 8sin(ωt-π/4). ωt = π/2. v (t) = 8sin(π/2-π/4) = 8sin45⁰=8(0.707) = 5.66V.

3. The value of the sine wave at some particular instant is called?
a) peak value
b) peak to peak value
c) instantaneous value
d) average value
View Answer

Answer: c
Explanation: The value of the sine wave at some particular instant is called instantaneous value. This value is different at different points along the waveform.
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4. The maximum value of the wave during a positive half cycle or maximum value of the wave during negative cycle is called?
a) instantaneous value
b) peak value
c) peak to peak value
d) average value
View Answer

Answer: b
Explanation: The maximum value of the wave during positive half cycle or maximum value of the wave during negative cycle is called peak value. Since the values of these two are equal in magnitude, a sine wave is characterized by a single peak value.

5. The total area under the complete curve divided by the distance of the curve is called?
a) peak to peak value
b) RMS value
c) average value
d) effective value
View Answer

Answer: c
Explanation: The total area under the complete curve divided by the distance of the curve is called average value. The average value of a sine wave over on e complete cycle is always zero.
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6. The value from positive to negative peak of the sine wave is called?
a) effective value
b) average value
c) peak value
d) peak to peak value
View Answer

Answer: d
Explanation: The value from positive to negative peak of the sine wave is called peak to peak value of a sine wave.

7. The RMS value of sine wave is?
a) 0.707Vp
b) 0.607Vp
c) 0.807Vp
d) 0.907Vp
View Answer

Answer: a
Explanation: The root mean square value of a sine wave is a measure of the heating effect of the wave. The RMS value of sine wave is 0.707Vp.
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8. A wire is carrying a direct current of 20A and a sinusoidal alternating current of peak value 20A. Find the rms value of the resultant current.
a) 24
b) 24.5
c) 25
d) 25.5
View Answer

Answer: b
Explanation: Direct current = 20A, sinusoidal alternating current of peak value = 20A. The rms value of the combined wave = √(202+202/2) = 24.5A.

9. The peak factor of the sinusoidal waveform is?
a) 4
b) 2
c) 1.414
d) 8
View Answer

Answer: c
Explanation: The peak factor of any waveform is defined as the ratio of the peak value of the wave to the rms value of the wave. Peak factor = Vp/(Vrms) = Vp/(Vp/√2)=√2=1.414.
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10. The form factor of the sinusoidal waveform is?
a) 1.11
b) 2.22
c) 3.33
d) 4.44
View Answer

Answer: a
Explanation: Form factor of any waveform is defined as the ratio of the rms value to the average value of the wave. Form factor = Vrms/Vav = (Vp/√2)/0.637Vp=1.11.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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