Network Security Questions and Answers – Overview – I

This set of Network Security Multiple Choice Questions & Answers (MCQs) focuses on “Overview of Network Security”.

1. Number of Blocks in class C are –
a) 27
b) 28
c) 214
d) 29
View Answer

Answer: a
Explanation: Number of Blocks in class A are 27.

2. A router receives a packet with the destination address 132.7.21.84. Find the network address of the packet.
a) 1.32.7
b) 132.7
c) 13.27
d) 21.84
View Answer

Answer: b
Explanation: 132 is between 128 and 191, so it is Class B address i.e. n=16-bit. Therefore,
Network address 132.7
Host address 21.84

3. If the first address is First address = 18.14.12.0/22. What is the last address?
a) 18.14.15.128/22
b) 18.14.15.64/22
c) 18.14.15.32/22
d) 18.14.15.255/22
View Answer

Answer: d
Explanation: Last address = (any address) OR [NOT (network mask)].
The Last Address = 18.14.15.255/22.
advertisement
advertisement

4. Nsub = n + log2(N/Nsub) is used to find the suffix length.
a) True
b) False
View Answer

Answer: b
Explanation: Nsub = n + log2(N/Nsub) is used to find the prefix length.

5. Convert the following binary notation to hexadecimal notation –
10000000 00001011 00000011 00011111
a) 0x 80 0B 03 1E
b) 0x 81 0B 04 1E
c) 0x 80 0C 03 1F
d) 0x 80 0B 03 1F
View Answer

Answer: d
Explanation: Converting the binary value to their respective hex values yields 0x 80 0B 03 1F.

6. The first address in a range of addresses is 14.11.45.96. If the number of addresses in the range is 32, what is the last address?
a) 14.11.44.64
b) 14.11.44.128
c) 14.12.44.128
d) 14.11.45.127
View Answer

Answer: d
Explanation: Last Address = (14.11.45.96 + 0.0.0.31)_256 = 14.11.45.127.
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

7. In an IP packet, the value of HLEN is 516 and the value of the total length field is 002816.What is the efficiency of this datagram?
a) 80%
b) 50%
c) 66%
d) 75%
View Answer

Answer: b
Explanation:
Total number of bytes in the header = 5 x 4 = 20 bytes.
Total length = 0028_16 = 40 bytes.
Data carried by the packet = (40 – 20) = 20 bytes.
Efficiency = payload length / total length = 20/40= 50%.

advertisement

8. A packet has arrived in which the offset value is 100, the value of HLEN is 5 and the value of the total length field is 100. What is the number of the last byte
a) 880
b) 879
c) 881
d) 801
View Answer

Answer: b
Explanation:
Total data bytes = total length – header length = 80 bytes in this datagram.
Last byte is therefore 879.

9. Assume we need to download text documents at the rate of 100 pages per second. What is the required bit rate of the channel?
a) 1.846 Mbps
b) 1.536 Mbps
c) 2.4 Mbps
d) None of the Mentioned
View Answer

Answer: b
Explanation: Average No, of lines u=in each page = 24
Each line has 80 char.
Each char required 8 bits
100 x 24 x 80 x 8 = 1,536,000=1536 Mbps.
advertisement

10. Generate the CRC codeword for the data word 1101011011 using generator 10011. Also write both in the polynomial form.
a) 11010110110011
b) 11010110110110
c) 11010110111100
d) 11010110111110
View Answer

Answer: d
Explanation: Solve using polynomial division and then appending the remainder to the divisor.

11. A slotted ALOHA network transmits 200-bit frames using a shared channel with a 200-kbps bandwidth. Find the throughput if the system (all stations together) produces 1000 frames per second.
a) 92 frames
b) 368 frames
c) 276 frames
d) 151 frames
View Answer

Answer: b
Explanation: G =1 S=G×e−G=0.368 (36.8%)
Throughput = 1000 × 0.0368 = 368 frames.

12. After performing bit stuffing on the following stream : 01101111111111111110010, the output is-
a) 01101111101111101111100010
b) 01101111111111111110010111
c) 10010000000000000000001101
d) 01101111111111111111110010
View Answer

Answer: a
Explanation: Bit stuffing involves adding a 0 after every five 1s during transmission.

13. A device that helps prevent congestion and data collisions –
a) Switch
b) Hub
c) Gateway
d) Proxy Server
View Answer

Answer: a
Explanation: A switch is a device that splits large networks into smaller segments, decreasing the number of users sharing the same network resources and bandwidth.

14. Which one of these does not lie in the Link Layer of the TCP/IP Model?
a) DSL
b) IP
c) SONET
d) 802.11
View Answer

Answer: b
Explanation: IP (Internet Protocol) is a member of the Internet layer.

15. How many layers are present in the TCP/IP Reference model?
a) 6
b) 7
c) 5
d) 4
View Answer

Answer: d
Explanation: There are 4 layers in the TCP/IP reference model : Link, Internet, Transport and Application.

Sanfoundry Global Education & Learning Series – Cryptography and Network Security.

To practice all areas of Cryptography and Network Security, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.