Fluid Mechanics Questions and Answers – Viscosity – 1

This set of Fluid Mechanics Multiple Choice Questions & Answers (MCQs) focuses on “Viscosity – 1”.

1. Water flows between two plates of which the upper one is stationary and the lower one is moving with a velocity V. What will be the velocity of the fluid in contact with the upper plate?
a) V
b) N ⁄ 2
c) 2V
d) 0
View Answer

Answer: d
Explanation: According to the No-Slip condition, the relative velocity between the plate and the fluid in contact with it must be zero. Thus, the velocity of the fluid in contact with the upper plate is 0 and that with the lower plate is V.

2. The viscous force the relative motion between the adjacent layers of a fluid in motion.
Which one of the flowing fits best in the sentence?
a) opposes
b) never affects
c) facilitates
d) may effect under certain conditions
View Answer

Answer: a
Explanation: Viscosity is the internal friction of a fluid in motion. It is the property by the virtue of which the relative motion between two adjacent fluid layers is opposed.

3. The viscosity of a fluid in motion is 1 Poise. What will be it’s viscosity (in Poise) when the fluid is at rest?
a) 0
b) 0.5
c) 1
d) 2
View Answer

Answer: c
Explanation: Viscosity is the property of a fluid and is constant for a given fluid under given conditions, irrespective of the fact whether the fluid is at rest or in motion.
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4. Which of the following correctly states how the viscosities of a liquid and a gas will change with temperature?
a) Viscosity increases with the increase in temperature of a liquid and decreases with the increase in temperature of a gas
b) Viscosity increases with the increase in temperature of a liquid and increases with the increase in temperature of a gas
c) Viscosity decreases with the increase in temperature of a liquid and decreases with the increase in temperature of a gas
d) Viscosity decreases with the increase in temperature of a liquid and increases with the increase in temperature of a gas
View Answer

Answer: d
Explanation: For liquids, viscosity typically decreases with an increase in temperature. This is because as temperature increases, the kinetic energy of the liquid molecules also increases. As a result, the molecules move more rapidly and are less likely to stick together, leading to a decrease in viscosity. For gases, viscosity generally increases with an increase in temperature. This is due to the fact that at higher temperatures, gas molecules have greater kinetic energy and move more rapidly. As a result, they collide more frequently and with greater force, leading to an increase in viscosity.

5. Which one of the following is not a unit of dynamic viscosity?
a) Pa-s
b) N-s/m2
c) Poise
d) Stokes
View Answer

Answer: d
Explanation: Find the following is/not a unit of dynamic viscosity in given figure
where F= viscous force, A= area, du ⁄ dx = velocity gradient, μ = co-effcient of viscosity. Therefore,
The following is/not a unit of dynamic viscosity is Stokes
SI unit of μ is N-s/m2 = Pa-s and CGS unit of μ is dyne-s/cm2. 1 Poise= 1 dyne-s/cm2 and 1 Stokes= 1 cm2/s. Thus, Stokes is not an unit of μ, rather it is a unit of kinematic viscosity υ.

6. Which of the following is a unit of dynamic viscosity?
a) [M1 L1 T-1].
b) [M1 L-1 T-1].
c) [M1 L-2 T-2].
d) [M1 L-2 T-2].
View Answer

Answer: b
Explanation: Find the following is/not a unit of dynamic viscosity in given figure
where F= viscous force, A= area, du ⁄ dx = velocity gradient, μ = co-effcient of viscosity. Therefore,
Find the following is/not a unit of dynamic viscosity in given figure
The following is a unit of dynamic viscosity is [M1 L-1 T-1]

7. Which one of the following is the CGS unit of dynamic viscosity?
a) Stokes
b) Pa-s
c) m2/s
d) Poise
View Answer

Answer: d
Explanation: Find the following is/not a unit of dynamic viscosity in given figure
where F= viscous force, A= area, du ⁄ dx = velocity gradient, μ = co-effcient of viscosity. Therefore,
Find the following is/not a unit of dynamic viscosity in given figure
CGS unit of μ is = dyne-s/cm2. 1 Poise= 1 dyne-s/cm2 and 1 Stokes= 1 cm2/s. Thus, the CGS unit of μ will be Poise. Stokes is the CGS unit of kinematic viscosity.
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8. The dynamic viscosity of a fluid is 1 Poise. What should one multiply to it to get the answer in N-s/m2?
a) 0.1
b) 1
c) 10
d) 100
View Answer

Answer: a
Explanation:
1 Poise = 1 dyne-s/cm2 Dynamic viscosity of fluid is 1 Poise

9. Which of the following is a unit of kinematic viscosity?
a) Stokes
b) Pa-s
c) m2=s
d) Poise
View Answer

Answer: a
Explanation: ν = μ/ρ, where ν = kinematic viscosity, μ = dynamic viscosity and ρ = density of the fluid. Unit of μ is dyne-s/cm2 and that of ρ is kg/cm3.
Thus, the unit of ν is cm2/s = Stokes Poise is the unit of dynamic viscosity.
1 Poise = 1 dyne-s/cm2 Dynamic viscosity of fluid is 1 Poise
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10. Which of the following is the dimension of kinematic viscosity?
a) [L1 T-1].
b) [L1 T-2].
c) [L2 T-1].
d) [L2 T-2].
View Answer

Answer: c
Explanation: ν = μ/ρ, where ν = kinematic viscosity, μ = dynamic viscosity and ρ = density of the fluid.
The following is the dimension of kinematic viscosity is [L2 T-1]

11. The kinematic viscosity of a fluid is 0.1 Stokes. What will be the value is m2/s?
a) 10-2
b) 10-3
c) 10-4
d) 10-5
View Answer

Answer: d
Explanation: 1Stokes = 1cm2/s = 10-4m2/s Therefore, 0.1Stokes = 10-1cm2/s = 10-5m2/s.

12. The shear stress at a point in a liquid is found to be 0.03 N/m2. The velocity gradient at the point is 0.15 s-1. What will be it’s viscosity (in Poise)?
a) 20
b) 2
c) 0.2
d) 0.5
View Answer

Answer: b
Explanation: Find the following is/not a unit of dynamic viscosity in given figure
where F= viscous force, A= area, du ⁄ dx = velocity gradient, μ = co-effcient of viscosity. Therefore,
Viscosity is 2 if velocity gradient at the point is 0.15 s-1

13. The space between two plates (20cm*20cm*1cm), 1 cm apart, is filled with a liquid of viscosity 1 Poise. The upper plate is dragged to the right with a force of 5N keeping the lower plate stationary.
Find velocity of flow at point 0.5 cm below lower surface of upper plate
What will be the velocity in m/s of flow at a point 0.5 cm below the lower surface of the upper plate if linear velocity profile is assumed for the flow?
a) 1.25
b) 2.5
c) 12.5
d) 0.25
View Answer

Answer: c
Explanation: The velocity of flow at point 0.5 cm below lower surface of upper plate is 12.5
where Fν = viscous force, A = area, du ⁄ dx = velocity gradient, μ = co-effcient of viscosity. If linear velocity profile is assumed, du⁄dx = U/x, where U = velocity of the upper plate and x = distance between the two plates. Now, the viscous force Fv = -F= -5N. Substituting all the values in the equation, U becomes 12.5 m/s.

Sanfoundry Global Education & Learning Series – Fluid Mechanics.

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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