C# Program to Find a Number using Pythagoras Theorem

This is a C# Program to find a number using pythagoras theorem.

Problem Description

This C# Program Finds a Number using Pythagoras Theorem.

Problem Solution

Here the pythagoras theorem is used to find the other number.

Program/Source Code

Here is source code of theC# Program to Find a Number using Pythagoras Theorem. The C# program is successfully compiled and executed with Microsoft Visual Studio. The program output is also shown below.

/*
 *  C# Program to Find a Number using Pythagoras Theorem
 */
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
class Program
{
    static void Main(string[] args)
    {
        double a, b, c;
        Console.WriteLine("Enter the First Value ");
        a = double.Parse(Console.ReadLine());
        Console.WriteLine("Enter the Second Value ");
        b = double.Parse(Console.ReadLine());
        c = Math.Sqrt(a * a + b * b);
        Console.WriteLine("The Other Number is : {0}", c);
        Console.ReadLine();
 
    }
}
Program Explanation

In this C# Program, we are reading the first Value and second value using ‘a’ and ‘b’ variables respectively. The pythagoras theorem is used to find the other number.
Multiply the value of ‘a’ variable with the value of ‘a’ variable and the value of ‘b’ variable with value of ‘b’ variable. Add both the multiplied value and take the square root of that value.

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Runtime Test Cases
 
Enter the First Value
3
Enter the Second Value
4
The Other Number is : 5

Sanfoundry Global Education & Learning Series – 1000 C# Programs.

If you wish to look at all C# Programming examples, go to 1000 C# Programs.

If you find any mistake above, kindly email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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