C++ Program to Find Single Source Shortest Path in DAG

This C++ program displays the shortest path traversal from a particular node to every other node present inside the graph relative to the former node.

Here is the source code of the C++ program of the Djikstra’s Algoritm of finding shortest paths from the first node in graph to every other node with the shortest path length displayed beside each pair of vertices.This C++ program is successfully compiled and run on DevCpp,a C++ compiler.The program output is given below.

  1. /*
  2.  * C++ Program to find SSSP(Single Source Shortest Path) 
  3.  * in DAG(Directed Acyclic Graphs)
  4.  */
  5. #include <iostream>
  6. #include <conio.h>
  7. using namespace std;
  8. #define INFINITY 999
  9. struct node
  10. {
  11.    int from;
  12. }p[7];
  13. int c = 0;
  14. void djikstras(int *a,int b[][7],int *dv)
  15. {
  16.     int i = 0,j,min,temp;
  17.     a[i] = 1;
  18.     dv[i] = 0;
  19.     p[i].from = 0;
  20.     for (i = 0; i < 7;i++)
  21.     {
  22.         if (b[0][i] == 0)
  23.         {
  24.             continue;
  25.         }
  26.         else
  27.         {
  28.             dv[i] = b[0][i];
  29.             p[i].from = 0;
  30.         }
  31.     }
  32.     while (c < 6)
  33.     {
  34.         min = INFINITY;
  35.         for (i = 0; i < 7; i++)
  36.         {
  37.             if (min <= dv[i] || dv[i] == 0 || a[i] == 1)
  38.             {
  39.                 continue;
  40.             }
  41.             else if (min > dv[i])
  42.             {
  43.                 min = dv[i];
  44.             }
  45.         }
  46.         for (int k = 0; k < 7; k++)
  47.         {
  48.             if (min == dv[k])
  49.             {
  50.                 temp = k;
  51.                 break;
  52.             }
  53.             else
  54.             {
  55.                 continue;
  56.     	    }
  57.         }
  58.         a[temp] = 1;
  59.         for (j = 0; j < 7; j++)
  60.         {
  61.             if (a[j] == 1 || b[temp][j] == 0)
  62.             {
  63.                 continue;
  64.             }
  65.             else if (a[j] != 1)
  66.             {
  67.                 if (dv[j] > (dv[temp] + b[temp][j]))
  68.                 {
  69.                     dv[j] = dv[temp] + b[temp][j];
  70.                     p[i].from = temp;
  71.                 }
  72.             }
  73.         }
  74.         c++;
  75.     }  
  76.     for (int i = 0; i < 7; i++)
  77.     {
  78.         cout<<"from node "<<p[i].from<<" cost is:"<<dv[i]<<endl;
  79.     } 
  80. }       
  81. int main()
  82. {
  83.     int a[7];
  84.     int dv[7];
  85.     for(int k = 0; k < 7; k++)
  86.     {
  87.         dv[k] = INFINITY;
  88.     }
  89.     for (int i = 0; i < 7; i++)
  90.     {
  91.         a[i] = 0;
  92.     }
  93.     int b[7][7];
  94.     for (int i = 0;i < 7;i++)
  95.     {
  96.         cout<<"enter values for "<<(i+1)<<" row"<<endl;
  97.         for(int j = 0;j < 7;j++)
  98.         {
  99.             cin>>b[i][j];
  100.         }
  101.     }
  102.     djikstras(a,b,dv);
  103.     getch();
  104. }

Output
enter values for 1 row
0
3
6
0
0
0
0
enter values for 2 row
3
0
2
4
0
0
0
enter values for 3 row
6
2
0
1
4
2
0
enter values for 4 row
0
4
1
0
2
0
4
enter values for 5 row
0
0
4
2
0
2
1
enter values for 6 row
0
0
2
0
2
0
1
enter values for 7 row
0
0
0
4
1
1
0
from node 0 to node 0 minimum cost is:0
from node 0 to node 1 minimum cost is:3
from node 0 to node 2 minimum cost is:5
from node 0 to node 3 minimum cost is:6
from node 0 to node 4 minimum cost is:8
from node 0 to node 5 minimum cost is:7
from node 0 to node 6 minimum cost is:8

Sanfoundry Global Education & Learning Series – 1000 C Programs.

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Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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