This C Program calculates the number of integers divisible by 5. This program checks if the given number is divisible by 5 and then prints an appropriate message.

Here is source code of the C program to calculate the number of integers divisible by 5. The C program is successfully compiled and run on a Linux system. The program output is also shown below.

`/*`

`* C program to find the number of integers divisible by`

`* 5 between the given range num1 and num2, where num1 < num2.`

`*`

`* Also find the sum of all these integer numbers which are divisible`

`* by 5 and display the total.`

`*/`

`#include <stdio.h>`

void main()

`{`

int i, num1, num2, count = 0, sum = 0;

printf("Enter the value of num1 and num2 \n");

scanf("%d %d", &num1, &num2);

`/* Count the number and compute their sum*/`

printf("Integers divisible by 5 are \n");

for (i = num1; i < num2; i++)

`{`

if (i % 5 == 0)

`{`

printf("%3d,", i);

`count++;`

sum = sum + i;

`}`

`}`

printf("\n Number of integers divisible by 5 between %d and %d =

%d\n", num1, num2, count);

printf("Sum of all integers that are divisible by 5 = %d\n", sum);

`}`

advertisements

$ cc pgm18.c $ a.out Enter the value of num1 and num2 12 17 Integers divisible by 5 are 15, Number of integers divisible by 5 between 12 and 17 = 1 Sum of all integers that are divisible by 5 = 15

**Sanfoundry Global Education & Learning Series – 1000 C Programs.**

Here’s the list of Best Reference Books in C Programming, Data-Structures and Algorithms

If you wish to look at other example programs on Simple C Programs, go to Simple C Programs. If you wish to look at programming examples on all topics, go to C Programming Examples.